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End Of Einstein
January 28, 2009 by Anonymous, 43 weeks 8 hours ago
Comment id: 34051
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Kepler (demolish) Vs Einstein's
Ending Einstein's space jail of time in 2009 that led to fraud Symbol E=mc²
Areal velocity is constant: r² ?' =h Kepler's Law
h = 2? a b/T; b=a? (1-?²); a = mean distance value; ? = eccentricity
r² ?'= h = S² w'
S = r exp (? wt); h = [r² Exp (2iwt)] w'=r²?'
w' = (?') exp [-2(i wt)]
w'= (h/r²) [cosine 2(wt) - ? sine 2(wt)] = (h/r²) [1- 2sine² (wt) - ? sin 2(wt)]
w' = w'(x) + ? w'(y) ; w'(x) = (h/r²) [ 1- 2sine² (wt)]
? w'= w'(x) – (h/r²) = - 2(h/r²) sine² (wt) = - 2(h/r²) (v/c) ² v/c=sine wt
(h/ r²)(Perihelion/Periastron)= [2?a.a? (1-?²)]/Ta² (1-?) ²= [2?? (1-?²)]/T (1-?) ²
? w' = [w'(x) – h/r²] = -4? {[? (1-?²)]/T (1-?) ²} (v/c) ² radian per second
{x [180/?;degrees]x[100years=36526days;century]x[3600;seconds in degree]
? w" = (-720x36526x3600/T) {[? (1-?²]/(1-?)²} (v/c)² seconds of arc per century
This Kepler's Equation solves all the problems Einstein and all physicists could not solve
DI Her Binary starts systems
The circumference of an ellipse: 2?a (1 - ?²/4 + 3/16(?²)²- --.) ? 2?a (1-?²/4); R =a (1-?²/4) v=? [G m M / (m + M) a (1-?²/4)] ? ? [GM/a (1-?²/4)]; m<